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8. FORCE AND LAWS OF MOTION
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A $8000 \,kg$ engine pulls a train of $5 $ wagons, each of $2000\, kg$, along a horizontal track. If the engine exerts a force of $40000 \,N $ and the track offers a friction force of $5000\, N$, then calculate: the acceleration(in $m/s^2$) of the train
A
$1.454$
B
$2.645$
C
$0.965$
D
$1.944$
Solution
Acceleration of the train $= a$
The engine exerts a force of $40000 \,N $ on all the five wagons.
Net accelerating force on the wagons, $F_a = 35000\, N$
Mass of the wagons, $m =$ Mass of a wagon $\times $ Number of wagons
Mass of a wagon $= 2000\, kg$
Number of wagons $= 5$
$\therefore $ $m = 2000 \times 5 = 10000\, kg$
Total mass (including the mass of engine), $M = m + 8000 = 18000 \,kg$
$F_a = Ma$
$\Rightarrow a=\frac{F_{a}}{M}=\frac{35000}{18000}=1.944\, m / s ^{2}$
Std 9
Science
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