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4.Principles of Inheritance and Variation
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A normalvisioned man whose father was colour blind, marries a woman whose father was also colourblind. They have their first child as a daughter. What are the chances that this child would be colour blind ?
A
$1$
B
Zero percent
C
$0.25$
D
$0.5$
(AIPMT-2012)
Solution
(b): In the given condition the chances of childto be colourblindis zero percent. It can be understoodby the given cross :
Standard 12
Biology
Similar Questions
:Match the columns :
| Column $I$ |
Column $II$ |
| $(a)$ Sickle cell anaemia | $(x)$ Homogentisic acid |
| $(b)$ Alkaptonuria | $(y)$ Melanin pigmentsare absent |
| $(c)$ Albinism | $(z)$ More amount of phenyl alanine |
| $(d)$ Phenyl Ketonuria | $(w)$ Defective haemoglobin |
easy
