A sum of ₹ 1260 is borrowed from a money lend | vedclass

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Question

(a) Here, $P=1260$ and $R=10$. .

Annual instalment

$=\frac{P}{\left(\frac{100}{100+R}\right)+\left(\frac{100}{100+R}\right)^{2}}=\frac{1260}{\fr

Vedclass · Accepted Answer

$726$

Vedclass · Answer

(a) Here, $P=1260$ and $R=10$. .

Annual instalment

$=\frac{P}{\left(\frac{100}{100+R}ight)+\left(\frac{100}{100+R}ight)^{2}}=\frac{1260}{\frac{100}{110}+\left(\frac{100}{110}ight)^{2}}$

$=\frac{1260}{\frac{100}{110}\left(1+\frac{100}{110}ight)}=1260 	imes \frac{110}{100} 	imes \frac{110}{210}=₹ 726$

A sum of ₹ $1260$ is borrowed from a money lender at $10 \%$ p.a. compounded annually. If the amount is to be paid back in two equal annual instalments, find out the annual instalment (In ₹).

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