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6.Interest
medium
An amount of money at compound interest grows up to ₹ $3,840$ in $4$ years and up to ₹ $3,936$ in $5$ years. Find the rate of interest (In $\%$)
A
$2.5$
B
$2$
C
$3.5$
D
$2.05$
Solution
(a) $\quad A=P\left(1+\frac{R}{100}\right)^{T}$
$\therefore \quad 3840=P\left(1+\frac{R}{100}\right)^{4}$
$3936=P\left(1+\frac{R}{100}\right)^{5}$
Dividing equation (2) by equation (1), we have
$\frac{3936}{3840}=1+\frac{R}{100} \Rightarrow \frac{R}{100}=\frac{3936}{3840}-1$
$=\frac{3936-3840}{3840}=\frac{96}{3840}$
$\Rightarrow \quad R=\frac{96}{3840} \times 100=2.5 \%$
Standard 13
Quantitative Aptitude
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