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Question

$\int \mathrm{d} \mathrm{v}=-\int \mathrm{E} \mathrm{d} \mathrm{x}$

$\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{0}=-\int_{0}^{2} 30 \mathrm{x}^{2} \mathrm

Vedclass · Accepted Answer

$-80$

Vedclass · Answer

$\int \mathrm{d} \mathrm{v}=-\int \mathrm{E} \mathrm{d} \mathrm{x}$

$\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{0}=-\int_{0}^{2} 30 \mathrm{x}^{2} \mathrm{d} \mathrm{x}$

$=-80$

Assume that an electric field $\overrightarrow E = 30{x^2}\hat i$ exists in space. Then the potential difference $V_A -V_O$, where $V_O$ is the potential at the origin and $V_A$ the potential at $x = 2\, m$ is

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