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4.Chemical Bonding and Molecular Structure
normal
Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule $B_2$ is
A
$1$ and diamagnetic
B
$0$ and diamagnetic
C
$1$ and paramagnetic
D
$0$ and paramagnetic
(IIT-2010)
Solution
$\mathrm{B}_2(10)=\sigma_{1 \mathrm{~s}^2} \sigma_{1 \mathrm{~s}^2}^* \sigma_{2 \mathrm{~s}^2} \sigma_{2 \mathrm{~s}^2}^* \pi_{2 \mathrm{p}_2^2}$
Bond order $=\frac{6-4}{2}=1$
(nature diamagnetic as no unpaired electron)
Std 11
Chemistry