If  $f(x) = \sqrt {{x^2} + x}  + \frac{{{{\tan }^2}\alpha }}{{\sqrt {{x^2} + x} }},\alpha  \in (0,\pi /2),x > 0$ then value of $f(x)$ is greater than or equal to-

  • A

    $2$

  • B

    $2 \tan \alpha$

  • C

    $\frac{5}{2}$

  • D

    $\sec \alpha$

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