If $A$ and $B$ are any two events, then $P(\bar A \cap B) = $
$P(\bar A)\,\,\,P(\bar B)$
$1 - P(A) - P(B)$
$P(A) + P(B) - P(A \cap B)$
$P(B) - P(A \cap B)$
(d) It is a fundamental concept.
A die is thrown. Let $A$ be the event that the number obtained is greater than $3.$ Let $B$ be the event that the number obtained is less than $5.$ Then $P\left( {A \cup B} \right)$ is
The probability that at least one of the events $A$ and $B$ occurs is $3/5$. If $A$ and $B$ occur simultaneously with probability $1/5$, then $P(A') + P(B')$ is
Check whether the following probabilities $P(A)$ and $P(B)$ are consistently defined $P ( A )=0.5$, $ P ( B )=0.4$, $P ( A \cap B )=0.8$
Let $A$ and $B$ be two events such that the probability that exactly one of them occurs is $\frac{2}{5}$ and the probability that $A$ or $B$ occurs is $\frac{1}{2}$ then the probability of both of them occur together is
If $A$ and $B$ are two independent events, then $P\,(A + B) = $
Confusing about what to choose? Our team will schedule a demo shortly.
