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1.Solution and Colligative properties
easy
If $x$ gram of non-volatile, non-electrolytic solute is dissolved in $114\ g$ octane to reduce its vapour pressure to $80\%$ of that of pure octane then $x$ is ........... $g$. (Molar mass solute $= 40\ g/mole$)
A
$10$
B
$5$
C
$20$
D
$40$
Solution
${\frac{-\Delta P}{P^{\theta}}=\frac{n_{2}}{n_{1}+n_{2}}}$
${\Rightarrow 0.2 \times 1=0.8 \times \frac{x}{40}}$
${\Rightarrow x=10\, g}$
Standard 12
Chemistry
