$(i)$ Clearly, the distance of $P$ from $y$ -axis is 3 units and that of from $x$ -axis is $2$ units. since $P$ lies in the first quadrant, so its coordinate are $(3,2)$ Point $R$ lies on $x$ – axis and its distance from $y$ and $x$ -axes are $3$ and $0$ units respectively.

So, its coordinates are $(3,0)$ Clearly, point $Q$ lies in the fourth quadrant. The distance of $Q$ from $y$ -axis is $3$ units and from $x$ -axis is $1$ unit.

So, the coordinates of $Q(3,-1)$

$(ii)$ From the given figure (graph), we find that the points $L$ and $M$ lie on the same straight line. So, $L$ and $M$ are collinear.

Hence, the difference between the abscissa of the points $L$ and $M$ is $0 .$