In a city 20% persons read English newspaper, 40% read Hindi newspaper and 5% read both newspapers.

English

Gujarati

Hindi

14.Probability

easy

In a city $20\%$ persons read English newspaper, $40\%$ read Hindi newspaper and $5\%$ read both newspapers. The percentage of non-reader either paper is

A

$60$

B

$35$

C

$25$

D

$45$

Solution

(d) $P(A) = \frac{1}{5},$ $P(B) = \frac{2}{5}$ and $P(A \cap B) = \frac{1}{{20}}$

Then $P(\bar A \cap \bar B) = 1 – P(A \cup B)$

$ = 1 – \left[ {\frac{1}{5} + \frac{2}{5} – \frac{1}{{20}}} \right] = \frac{9}{{20}}$ i.e., $45\%$.

Standard 11

Mathematics

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