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In a mixture of $A$ and $B$ components shows negative deviation when
$A-B$ interaction is weaker than $A-A$ and $B-B$ interaction
$A-B$ interaction is stronger than $A-A$ and $B-B$ interaction
$\Delta {V_{\operatorname{mi} x}}\, > \,0,\,\Delta {S_{\operatorname{mi} x}}\, > \,0$
$\Delta {V_{\operatorname{mi} x}}\, = \,0,\,\Delta {S_{\operatorname{mi} x}}\, =\,0$
Solution
In a mixture component $A$ and component $B$ Shows negative Deviation as, $\Delta V _{\text {mixing }}\,<\,0$
i.e. For Negative Deviation, $\Delta V _{\text {mixing }}= O , \Delta H _{\text {mixing }}=-$ ve
Because, the forces of attraction between components $A$ and $B$ is greater.
Due to that the tendency of escaping of molecules $A B$ from solution becomes less than that of pure liquids.
$A – B$ attractive forces is greater than $A – A$ and $B – B$ attractive forces.
