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4.Average

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The average of $50$ numbers is $38 .$ If two numbers, namely $45$ and $55$ are discarded, the average of the remaining numbers is

A

$36.5$

B

$37.0$

C

$37.5$

D

$37.9$

Solution

Average $=\frac{\text { sum of elements }}{\text { number of elements }}$

Given, initial mumber of elements $=50$

Initial average $=38$

Sum of elements $=50 \times 38=1900$.

Now as two numbers are discarded, hence number of elements left $=48$.

Sum of elements after discarding numbhers $=1900-55 -45$$=1800$

Hence, new average $=\frac{1800}{48}=37.5$

Std 13

Quantitative Aptitude

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