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1.Units, Dimensions and Measurement
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$1\ MW$ પાવર નું મૂલ્ય જો દળ,લંબાઇ અને સમયના નવા એકમો $10\ kg,\ 1\ dm$ અને $1\ minute$ હોય,તો કેટલું થાય?
A$2.16 \times {10^{12}}unit$
B$1.26 \times {10^{12}}unit$
C$2.16 \times {10^{10}}unit$
D$2 \times {10^{14}}unit$
Solution
$[P] = [M{L^2}{T^{ – 3}}]$
${n_2} = {n_1}{\left[ {\frac{{{M_1}}}{{{M_2}}}} \right]^x}\,{\left[ {\frac{{{L_1}}}{{{L_2}}}} \right]^y}\,{\left[ {\frac{{{T_1}}}{{{T_2}}}} \right]^z}$$ = 1 \times {10^6}\,{\left[ {\frac{{1\,kg}}{{10\,kg}}} \right]^1}\,{\left[ {\frac{{1m}}{{1\,dm}}} \right]^2}\,{\left[ {\frac{{1s}}{{1\min }}} \right]^{ – 3}}$ [$\,1MW = {10^6}W$]
$ = {10^6}\left[ {\frac{{1kg}}{{10kg}}} \right]\,{\left[ {\frac{{10\,dm}}{{1\,dm}}} \right]^2}\,{\left[ {\frac{{1sec}}{{60sec}}} \right]^{ – 3}}$$ = 2.16 \times {10^{12}}$unit
${n_2} = {n_1}{\left[ {\frac{{{M_1}}}{{{M_2}}}} \right]^x}\,{\left[ {\frac{{{L_1}}}{{{L_2}}}} \right]^y}\,{\left[ {\frac{{{T_1}}}{{{T_2}}}} \right]^z}$$ = 1 \times {10^6}\,{\left[ {\frac{{1\,kg}}{{10\,kg}}} \right]^1}\,{\left[ {\frac{{1m}}{{1\,dm}}} \right]^2}\,{\left[ {\frac{{1s}}{{1\min }}} \right]^{ – 3}}$ [$\,1MW = {10^6}W$]
$ = {10^6}\left[ {\frac{{1kg}}{{10kg}}} \right]\,{\left[ {\frac{{10\,dm}}{{1\,dm}}} \right]^2}\,{\left[ {\frac{{1sec}}{{60sec}}} \right]^{ – 3}}$$ = 2.16 \times {10^{12}}$unit
Std 11
Physics
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