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The pair of species that has the same bond order in the following is
$CO, NO^+$
$NO^-, CN^-$
$O_2, N_2$
$O_2, B_2$
Solution
$\sigma 1 \mathrm{s}^{2}, \sigma^{*} 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2}, \sigma^{*} 2 \mathrm{s}^{2}, \sigma 2 \mathrm{p}_{2}^{2}, \pi 2 \mathrm{p}_{\mathrm{x}}^{2} \approx \pi 2 \mathrm{p}_{\mathrm{x}}^{2}, \pi^{*} 2 \mathrm{p}_{\mathrm{x}}^{2} \approx \mathrm{\pi}^{*} 2 \mathrm{p}_{\mathrm{y}}^{2}$
Bond order $=\frac{N_{b}-N_{a}}{2}$ (where $N_{b}=$ number of electrons in bonding molecular orbital
$\mathrm{N}_{\mathrm{a}}=$ number of electrons in anti $-$ bonding molecular orbital)
$O_{2}^{2-}(8+8+2=18)$
$\mathrm{BO}=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}=\frac{10-8}{2}=1$
$\mathrm{B}_{2}(5+5=10)=\sigma 1 \mathrm{s}^{2}, \sigma^{*} 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2}, \sigma^{*} 2 \mathrm{s}^{2}, \pi 2 \mathrm{p}_{\mathrm{x}}^{1} \approx \pi 2 \mathrm{p}_{\mathrm{y}}^{1}$
$B O=\frac{6-4}{2}$
similarly, order of;
$O_{2}^{+}=2.5, \mathrm{NO}^{+}=3$
$\mathrm{NO}=2.5, \mathrm{CO}=3$
$\mathrm{N}_{2}=3$ and $\mathrm{O}_{2}=2$
$\sigma 1 \mathrm{s}^{2}, \sigma^{*} 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2}, \sigma^{*} 2 \mathrm{s}^{2}, \sigma 2 \mathrm{p}_{2}^{2}, \pi 2 \mathrm{p}_{\mathrm{x}}^{2} \approx \pi 2 \mathrm{p}_{\mathrm{y}}^{2}, \pi^{*} 2 \mathrm{p}_{\mathrm{x}}^{2} \approx \pi^{*} 2 \mathrm{p}_{\mathrm{y}}^{2}$
Bond order $=\frac{N_{\mathrm{b}}-\mathrm{N}_{a}}{2}$
(where $N_{b}=$ number of electrons in bonding molecular orbital
$\mathrm{N}_{a}=$ number of electrons in anti – bonding molecular orbital $O_{2}^{2-}(8+8+2=18)$
$\mathrm{BO}=\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}=\frac{10-\mathrm{g}}{2}=1$
$\mathrm{B}_{2}(5+5=10)=\sigma 1 \mathrm{s}^{2}, \sigma^{*} 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2}, \sigma^{*} 2 \mathrm{s}^{2}, \pi 2 \mathrm{p}_{\mathrm{x}}^{1} \approx \pi 2 \mathrm{p}_{\mathrm{y}}^{1}$
$B O=\frac{6-4}{2}$
similarty, order of:
$O_{2}^{+}=2.5, \mathrm{NO}^{+}=3$
$\mathrm{NO}=2.5, \mathrm{CO}=3$
$\mathrm{N}_{2}=3$ and $\mathrm{O}_{2}=2$
Similar Questions
Match each of the diatomic molecules in Column $I$ with its property / properties in Column $II$.
Column $I$ | Column $II$ |
$(A)$ $\mathrm{B}_2$ | $(p)$ Paramagnetic |
$(B)$ $\mathrm{N}_2$ | $(q)$ Undergoes oxidation |
$(C)$ $\mathrm{O}_2^{-}$ | $(r)$ Undergoes reduction |
$(D)$ $\mathrm{O}_2$ | $(s)$ Bond order $\geq 2$ |
$(t)$ Mixing of ' $\mathrm{s}$ ' and ' $\mathrm{p}$ ' orbitals |