વિધાન : Ozone is powerful oxidising agent in comparison to $O_2$.
કારણ : Ozone is diamagnetic but $O_2$ is paramagnetic.
વિધાન : Ozone is powerful oxidising agent in comparison to $O_2$.
કારણ : Ozone is diamagnetic but $O_2$ is paramagnetic.
- [AIIMS 2005]
- A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
- B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
- C
If the Assertion is correct but Reason is incorrect.
- D
If both the Assertion and Reason are incorrect.
Similar Questions
Give electron configuration, magnetic property, bond order and energy diagram for fluorine $\left( {{{\rm{F}}_2}} \right)$ molecule.
Give electron configuration, magnetic property, bond order and energy diagram for fluorine $\left( {{{\rm{F}}_2}} \right)$ molecule.
Four diatomic species are listed below. Identify the correct order in which the bond order is increasing in them
Four diatomic species are listed below. Identify the correct order in which the bond order is increasing in them
- [AIPMT 2008]
In which of the following transformations, the bond order has increased and the magnetic behaviour has changed
In which of the following transformations, the bond order has increased and the magnetic behaviour has changed
Write the important conditions required for the linear combination of atomic orbitals to form molecular orbitals.
Write the important conditions required for the linear combination of atomic orbitals to form molecular orbitals.
Match $List-I$ with $List-II$.
$List-I$
$List-II$
$(A)$ $\Psi_{ MO }=\Psi_{ A }-\Psi_{ B }$
$(I)$ Dipole moment
$(B)$ $\mu=Q \times I$
$(II)$ Bonding molecular orbital
$(C)$ $\frac{N_{b}-N_{a}}{2}$
$(III)$ Anti-bonding molecualr orbital
$(D)$ $\Psi_{ MO }=\Psi_{ A }+\Psi_{ B }$
$(IV)$ Bond order
Match $List-I$ with $List-II$.
| $List-I$ | $List-II$ |
| $(A)$ $\Psi_{ MO }=\Psi_{ A }-\Psi_{ B }$ | $(I)$ Dipole moment |
| $(B)$ $\mu=Q \times I$ | $(II)$ Bonding molecular orbital |
| $(C)$ $\frac{N_{b}-N_{a}}{2}$ | $(III)$ Anti-bonding molecualr orbital |
| $(D)$ $\Psi_{ MO }=\Psi_{ A }+\Psi_{ B }$ | $(IV)$ Bond order |
- [JEE MAIN 2022]