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6.Interest
hard
₹ 6,100 was partly invested in Scheme A at 10% p.a. compound interest (compounded annually) for 2 years and partly in Scheme B at 10% p.a. simple interest for 4 years. Both the schemes pay equal interests. How much was invested (In ₹) in Scheme A?
A
3750
B
4500
C
4000
D
3250
Solution
(c) Let amount invested in scheme A=₹x
Let amount invested in scheme B=₹(6100−x)
P1[(1+R1100)T1−1]=P2R2T2100
x=[(1+10100)2−1]
x=(6100−x)×10×4100
⇒x×[(1110)2−1]=4(6100−x10)
x×(121−100100)=4(6100−x)10
⇒21x100=24400−4x10
21x=244000−40x
21x+40x=244000
61x=244000
x=₹4000
Standard 13
Quantitative Aptitude