- Home
- Standard 13
- Quantitative Aptitude
6.Interest
hard
₹ $3757$ is to be divided between $A$ and $B$ such that $A's$ share at the end of $7$ years may be equal to $B$ 's share at the end of $9$ years. If rate per cent be $10 \%$ p.a. compound interest, $B$ 's share is (In ₹)
A
$1700$
B
$1500$
C
$2057$
D
$1400$
Solution
(a) Let $A$ 's share $=₹ x$
$B$ 's share $=₹(3757-x)$
$x\left(1+\frac{10}{100}\right)^{7}=(3757-x)\left(1+\frac{10}{100}\right)^{9}$
$x=(3757-x)\left(\frac{11}{10}\right)^{2}$
$x\left(1+\frac{121}{100}\right)=\frac{3757 \times 121}{100}$
$x=\frac{3757 \times 121}{221}$
$=₹ 2057$
$B$ 's share $=₹(3757-2057)=₹ 1700$
Standard 13
Quantitative Aptitude