Gujarati
Hindi
4-2.Friction
medium

........ $N$  the maximum force for which both the block will move with same acceleration.

A

$16$

B

$32$

C

$48$

D

$8$

Solution

Pseudo force on 4 kg block $=\mathrm{ma}$

$\therefore \mathrm{ma}=\mu \mathrm{mg} \Rightarrow \mathrm{a}=0.4 \times 10=4 \mathrm{m} / \mathrm{s}^{2}$

as both the blocks will move with same

acc$”a”$

${F=(4+8) a}$

${=12 \times 4=48 \mathrm{N}}$

Standard 11
Physics

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