Gujarati
Hindi
12.Kinetic Theory of Gases
normal

$CO_2(O-C-O)$ is a triatomic gas. Mean kinetic energy of one gram gas will be (If $N-$ Avogadro's number, $k-$ Boltzmann's constant and molecular weight of $CO_2 = 44$ )

A

$(3 / 88) NkT$

B

$(5 / 88) NkT$

C

$(6 / 88) NkT$

D

$(7 / 88) NkT$

Solution

Mean kinetic energy for $\mu$ mole gas $=\mu \cdot \frac{f}{2} R T$

$\therefore E=\mu \frac{7}{2} R T=\left(\frac{m}{M}\right) \frac{7}{2} N k T$

$=\frac{1}{44}\left(\frac{7}{2}\right) N k T=\frac{7}{88} N k T$

[As $\left.f=7 \text { and } M=44 \text { for } C O_{2}\right]$

Standard 11
Physics

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