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10-1.Thermometry, Thermal Expansion and Calorimetry
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$2\,g$ of steam condenses when passed through $40\,g$ of water initially at $25\,^oC$. The condensation of steam raises the temperature of water to $54.3\,^oC$, ........ $cal/g$ is the latent heat of steam ?
A
$540$
B
$536$
C
$270$
D
$480$
Solution
Heat gain = Heat loose
$\mathrm{m}_{\mathrm{w}} \mathrm{s}_{\mathrm{w}} \Delta \mathrm{T}=\mathrm{m}_{\mathrm{s}} \mathrm{L}+\mathrm{m}_{\mathrm{w}} \mathrm{s}_{\mathrm{w}}(\Delta \mathrm{T})$
$40 \times 1 \times(54.3-25)=2 \times \mathrm{L}+2 \times 1 \times(100-54.3)$
$\mathrm{L}=540.3 \mathrm{cal} / \mathrm{g}$
Standard 11
Physics
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