Gujarati
Hindi
10-1.Thermometry, Thermal Expansion and Calorimetry
medium

$0.1\,m^3$ of water at $80\,^oC$ is mixed with $0.3\,m^3$ of water at $60\,^oC$. The final temperature of the mixture is ........ $^oC$

A

$65$

B

$70$

C

$60$

D

$75$

Solution

Let $T^{\circ} C$ be final temperature of the mixture.

According to principle of calorimetry,

Heat lost $=$ Heat gained

$\therefore \quad 0.1 \times 10^{3} \times s_{\text {water}} \times(80-T)$

$=0.3 \times 10^{3} \times s_{\text {water}} \times(T-60)$

$\Rightarrow T=65^{\circ} \mathrm{C}$

Standard 11
Physics

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