Assertion : Angle of repose is equal to the a | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\begin{array}{l}
The\,{m{maximum}}\,value\,of\,static\,friction\,up\
to\,which\,body\,does\,not\,move\,is\,called\,\
{m{limiting}}\,friction

Vedclass · Accepted Answer

If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.

Vedclass · Answer

$\begin{array}{l}
The\,{m{maximum}}\,value\,of\,static\,friction\,up\
to\,which\,body\,does\,not\,move\,is\,called\,\
{m{limiting}}\,friction.\
\,\,\,\,\,\,\,\,\,Angle\,of\,repose\,is\,defined\,as\,the\,angle\
\,\,\,\,\,\,\,\,\,\,of\,the\,inclined\,plane\,with\,horizontal\
\,\,\,\,\,\,\,\,\,\,such\,that\,a\,body\,placed\,on\,it\,is\,just\,\
\,\,\,\,\,\,\,\,\,\,begins\,to\,slide.\
\,\,\,\,\,\,\,\,\,In\,{m{limiting}}\,{m{condition,}}\
\,\,\,\,\,\,\,\,\,F = mg\sin \alpha \,and\,R = mg\cos \alpha \
\,\,\,\,\,\,\,\,\,where\,\alpha  - angle\,of\,repose.
\end{array}$

$\begin{array}{l}
\,\,So\,\frac{F}{R} = 	an \alpha \
\,\,\,\,\,\,\,\,\,\,	herefore \frac{F}{R} = {\mu _2} = 	an 	heta  = 	an \alpha \,\,\,\left( {	an 	heta  = {\mu _s}} ight)\
\,\,\,\,\,\,\,\,\,\,or\,	heta  = \alpha \
\,\,\,\,\,\,\,\,\,\,i.e,.\,angle\,of\,friciton\, = \,angle\,of\,repose.
\end{array}$

$Assertion$ : Angle of repose is equal to the angle of limiting friction.
$Reason$ : When the body is just at the point of motion, the force of friction in this stage is called limiting friction.

Similar Questions

A cyclist speeding at $18 \;km/h$ on a level road takes a sharp circular turn of radius $3\; m$ without reducing the speed. The co-efficient of static friction between the tyres and the road is $0.1$. Will the cyclist slip while taking the turn?

A block of mass $2 kg$ slides down an incline plane of inclination $30^o$. The coefficient of friction between block and plane is $0.5$. The contact force between block and plank is :

Why coefficient friction is considered as static friction ?

How do static friction oppose motion ? Value of coefficient of friction depend on which factors ?

A block of mass $1\,kg$ lies on a horizontal surface in a truck. The coefficient of static friction between the block and the surface is $0.6$ . If the acceleration of the truck is $5\,m\,s^{-2}$ . The frictional force acting on the block is ........ $N$

$Assertion$ : Angle of repose is equal to the angle of limiting friction. $Reason$ : When the body is just at the point of motion, the force of friction in this stage is called limiting friction.