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13.Nuclei
easy
$1 a.m.u.$ is equivalent to
A
$1.6 \times {10^{ - 12}}Joule$
B
$1.6 \times {10^{ - 19}}Joule$
C
$1.5\, \times {10^{ - 10}}Joule$
D
$1.5 \times {10^{ - 19}}Joule$
Solution
(c)$1 amu$ $ = 1.66 \times {10^{ – 27}}\,kg$
$E = m{c^2} = 1.66 \times {10^{ – 27}} \times {(3 \times {10^8})^2} = 1.5 \times {10^{ – 10}}\,J$
Standard 12
Physics
