1 a.m.u. is equivalent to

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13.Nuclei

easy

$1 a.m.u.$ is equivalent to

A

$1.6 \times {10^{ - 12}}Joule$

B

$1.6 \times {10^{ - 19}}Joule$

C

$1.5\, \times {10^{ - 10}}Joule$

D

$1.5 \times {10^{ - 19}}Joule$

Solution

(c)$1 amu$ $ = 1.66 \times {10^{ – 27}}\,kg$
$E = m{c^2} = 1.66 \times {10^{ – 27}} \times {(3 \times {10^8})^2} = 1.5 \times {10^{ – 10}}\,J$

Standard 12

Physics

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