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4.Average
medium
$16$ children are to be divided into two groups $A$ and $B$ of $10$ and $6$ children, respectively. The average marks obtained by the children of group $A$ is $75$ and that of all the children is $76 .$ Then, the average marks of the children of group $B$ is ?
A
$77 \frac{1}{3}$
B
$77 \frac{2}{3}$
C
$78 \frac{1}{3}$
D
$78 \frac{2}{3}$
Solution
Sum of the marks of all $16$ childern $=16 \times 76=1216$
Sum of the Marks obtain by group $A=75 \times 10=750$
Marks of graup $B=1216-750=466$
Average marks of Group $B=77 \frac{4}{6}=77 \frac{2}{3}$
Standard 13
Quantitative Aptitude
