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7.Gravitation
medium
$R$ is the radius of the earth and $\omega $ is its angular velocity and ${g_p}$ is the value of $g$ at the poles. The effective value of $g$ at the latitude $\lambda = 60^\circ $ will be equal to
A
${g_p} - \frac{1}{4}R{\omega ^2}$
B
${g_p} - \frac{3}{4}R{\omega ^2}$
C
${g_p} - R{\omega ^2}$
D
${g_p} + \frac{1}{4}R{\omega ^2}$
Solution
(a) $g = {g_p} – R{\omega ^2}{\cos ^2}\lambda $ = ${g_p} – {\omega ^2}R{\cos ^2}60^\circ $ = ${g_p} – \frac{1}{4}R{\omega ^2}$
Standard 11
Physics
