Frac{sin 60+cos 30}{1+sin 30+cos 60}=ldots ldots ldots

English

Gujarati

Hindi

8. Introduction to Trigonometry

easy

$\frac{\sin 60+\cos 30}{1+\sin 30+\cos 60}=\ldots \ldots \ldots$

A

$\frac{1}{\sqrt{2}}$

B

$\frac{1}{2}$

C

$1$

D

$\frac{\sqrt{3}}{2}$

Solution

$\frac{\sin 60+\cos 30}{1+\sin 30+\cos 60}=\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}$

Standard 10

Mathematics

Share

Similar Questions

Which of the following group truely match the data of Part $I$ with the data of Part $II$ ?

Part $I$ Part $II$

$1.$ $\cos(90-\theta)$ $a.$ $\sec \theta$

$2.$ $\cot(90-\theta)$ $b.$ $\sin \theta$

$3$ $\operatorname{cosec}(90-\theta)$ $c.$ $1$

$d.$ $\tan \theta$

medium

The value of $\left(\tan 1^{\circ} \tan 2^{\circ} \tan 3^{\circ} \ldots \tan 89^{\circ}\right)$ is

medium

$\sin (90-\theta)=\ldots \ldots \ldots$

easy

Given that $\sin \alpha=\frac{1}{2}$ and $\cos \beta=\frac{1}{2},$ then the value of $(\alpha+\beta)$ is

easy

If $\sec 4 A =\operatorname{cosec}( A -20),$ where $4 A$ is a measure of acute angle then the value of $A$ is $\ldots \ldots \ldots \ldots .$

medium