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8. Introduction to Trigonometry
easy
$\frac{\cos 50}{\sin 40}+\frac{\sin 15}{\cos 75}=\ldots \ldots \ldots \ldots$
A
$0$
B
$1$
C
$2$
D
$3$
Solution
$\frac{\cos 50}{\sin 40}+\frac{\sin 15}{\cos 75}=\frac{\sin (90-50)}{\sin 40}+\frac{\sin 15}{\sin (90-75)}$
$=\frac{\sin 40}{\sin 40}+\frac{\sin 15}{\sin 15}=1+1=2$
Standard 10
Mathematics