8. Introduction to Trigonometry
easy

$\frac{\cos 50}{\sin 40}+\frac{\sin 15}{\cos 75}=\ldots \ldots \ldots \ldots$

A

$0$

B

$1$

C

$2$

D

$3$

Solution

$\frac{\cos 50}{\sin 40}+\frac{\sin 15}{\cos 75}=\frac{\sin (90-50)}{\sin 40}+\frac{\sin 15}{\sin (90-75)}$

$=\frac{\sin 40}{\sin 40}+\frac{\sin 15}{\sin 15}=1+1=2$

Standard 10
Mathematics

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