Sin 48 sec 42+cos 48 operatorname{cosec} 42=ldots ldots ldots ldots

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8. Introduction to Trigonometry

easy

$\sin 48 \sec 42+\cos 48 \operatorname{cosec} 42=\ldots \ldots \ldots \ldots$

A

$2$

B

$1$

C

$\frac{3}{4}$

D

$0$

Solution

$\sin 48 \sec 42+\cos 48 \operatorname{cosec} 42$

$=\cos (90-48) \sec 42+\sin (90-48) \operatorname{cosec} 42$

$=\cos 42 \sec 42+\sin 42 \operatorname{cosec} 42$

$=1+1(\because \cos \theta \sec \theta=1 ; \sin \theta \operatorname{cosec} \theta=1)$

$=2$

Standard 10

Mathematics

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