Sin θ · cos (90-θ)=ldots ldots ldots

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8. Introduction to Trigonometry

easy

$\sin \theta \cdot \cos (90-\theta)=\ldots \ldots \ldots$

A

$\tan \theta$

B

$\sin ^{2} \theta$

C

$\cos ^{2} \theta$

D

$\sin \theta \cdot \sec \theta$

Solution

$\sin \theta \cos (90-\theta)=\sin \theta \sin \theta=\sin ^{2} \theta$

Standard 10

Mathematics

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