{d over {dx}}left( {{1 over {{x^4}sec x}}} right) =

English

Gujarati

Hindi

3-1.Vectors

normal

${d \over {dx}}\left( {{1 \over {{x^4}\sec x}}} \right) = $

A${{x\sin x + 4\cos x} \over {{x^5}}}$

B${{ - (x\sin x + 4\cos x)} \over {{x^5}}}$

C${{4\cos x - x\sin x} \over {{x^5}}}$

DNone of these

Solution

(b) $\frac{d}{{dx}}\left( {\frac{1}{{{x^4}\sec x}}} \right) = \frac{d}{{dx}}\left( {\frac{{\cos x}}{{{x^4}}}} \right)$$ = \frac{{{x^4}( – \sin x) – \cos x(4{x^3})}}{{{{({x^4})}^2}}}$
$ = \frac{{ – {x^3}(x\sin x + 4\cos x)}}{{{x^8}}} = \frac{{ – (x\sin x + 4\cos x)}}{{{x^5}}}$.

Standard 11

Physics

Given $A =\hat{ i }+\hat{ j }+\hat{ k }$ and $B =-\hat{ i }-\hat{ j }-\hat{ k }$, then $( A – B )$ will make angle with $A$

normal

If the angle between two vectors $A$ and $B$ is $120^{\circ}$, its resultant $C$ will be

normal

$100$ coplanner forces each equal to $10\,\,N$ act on a body. Each force makes angle $\pi /50$ with the preceding force. What is the resultant of the forces………. $N$

normal

Three forces acting on a body are shown in the figure. To have the resultant force only along the $y-$ direction, the magnitude of the minimum additional force needed is………$N$

normal

$ $

normal

${d \over {dx}}\left( {{1 \over {{x^4}\sec x}}} \right) = $

Solution

Similar Questions

Given $A =\hat{ i }+\hat{ j }+\hat{ k }$ and $B =-\hat{ i }-\hat{ j }-\hat{ k }$, then $( A – B )$ will make angle with $A$

If the angle between two vectors $A$ and $B$ is $120^{\circ}$, its resultant $C$ will be

$100$ coplanner forces each equal to $10\,\,N$ act on a body. Each force makes angle $\pi /50$ with the preceding force. What is the resultant of the forces………. $N$

Three forces acting on a body are shown in the figure. To have the resultant force only along the $y-$ direction, the magnitude of the minimum additional force needed is………$N$

$ $

Start a Free Trial Now