- Home
- Standard 11
- Chemistry
6-2.Equilibrium-II (Ionic Equilibrium)
hard
$Mg ^{2+}$ के घोल में $NaOH$ डालने पर $Mg ( OH )_2$ अवक्षेपित होता है। यदि $Mg ^{2+}$ का अंतिम सांद्रण $10^{-10}\, M$ है, तो घोल में $OH ^{-}$का सांद्रण $( M$ में) क्या है
$\left[ Mg ( OH )_2\right.$ घुलनशीलता गुणनफल $\left.=5.6 \times 10^{-12}\right]$
A$0.056$
B$0.12$
C$0.24$
D$0.025$
(KVPY-2017)
Solution
(c)
Given, $K_{ sp }\,\, Mg ( OH )_{2}=5.6 \times 10^{-12}$
Concentration of $Mg ^{2+}=10^{-10}\, M$
For the reaction,
$Mg ( OH )_{2} \rightleftharpoons Mg ^{2+}+2 OH ^{-}$
$K_{ sp } =\left[ Mg ^{2+}\right]\left[ OH ^{-}\right]^{2}$
$5.6 \times 10^{-12}=\left[10^{-10} M \right]\left[ OH ^{-}\right]^{2}$
$\frac{5.6 \times 10^{-12}}{10^{-10}} =\left[ OH ^{-}\right]^{2}$
$=\sqrt{5.6 \times 10^{-2}}=\left[ OH ^{-}\right]$
$\therefore \quad\left[ OH ^{-}\right] =0.24 \,M$
Note Due to common ion effect, the concentration of $OH ^{-}$gets suppressed.
Given, $K_{ sp }\,\, Mg ( OH )_{2}=5.6 \times 10^{-12}$
Concentration of $Mg ^{2+}=10^{-10}\, M$
For the reaction,
$Mg ( OH )_{2} \rightleftharpoons Mg ^{2+}+2 OH ^{-}$
$K_{ sp } =\left[ Mg ^{2+}\right]\left[ OH ^{-}\right]^{2}$
$5.6 \times 10^{-12}=\left[10^{-10} M \right]\left[ OH ^{-}\right]^{2}$
$\frac{5.6 \times 10^{-12}}{10^{-10}} =\left[ OH ^{-}\right]^{2}$
$=\sqrt{5.6 \times 10^{-2}}=\left[ OH ^{-}\right]$
$\therefore \quad\left[ OH ^{-}\right] =0.24 \,M$
Note Due to common ion effect, the concentration of $OH ^{-}$gets suppressed.
Standard 11
Chemistry
