Tan 1° tan 2° tan 3° tan 4° ........tan 89° =

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3.Trigonometrical Ratios, Functions and Identities

easy

$\tan 1^\circ \tan 2^\circ \tan 3^\circ \tan 4^\circ ........\tan 89^\circ = $

A

$1$

B

$0$

C

$\infty $

D

$1/2$

Solution

(a) $\tan 1^\circ \tan 2^\circ ….\tan 89^\circ $

$ = (\tan 1^\circ \tan 89^\circ )(\tan 2^\circ \tan 88^\circ )……$$ = 1 \times 1 \times 1…. = 1.$

Standard 11

Mathematics

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