Gujarati
10-1.Thermometry, Thermal Expansion and Calorimetry
medium

$50\, gm$ of ice at $0°C$ is mixed with $50\, gm$ of water at $80°C,$ final temperature of mixture will be........ $^oC$

A

$0$

B

$40$

C

$40$

D

$4$

Solution

(a) $ {\theta _{{\rm{mix}}}} = \frac{{{\theta _W} – \frac{{{L_i}}}{{{c_W}}}}}{2} = \frac{{80 – \frac{{80}}{1}}}{2} = 0$

Standard 11
Physics

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