+ 2,C and + 6,C two charges are repelling e | vedclass

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(d) Resultant charges after adding the $-2\,C$ be $( - \,2 + 2) = 0$ and $( - \,2 + 6) = + \,4\,C$ $==> F$ $ = \frac{{k\,{Q_1}{Q_2}}}{{{r^2}}} = k

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Zero

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(d) Resultant charges after adding the $-2\,C$ be $( - \,2 + 2) = 0$ and $( - \,2 + 6) = + \,4\,C$ $==> F$ $ = \frac{{k\,{Q_1}{Q_2}}}{{{r^2}}} = k 	imes \frac{{0 	imes 4}}{{{r^2}}} = 0$

$ + 2\,C$ and $ + 6\,C$ two charges are repelling each other with a force of $12\,N$. If each charge is given $ - 2\,C$ of charge, then the value of the force will be

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