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6-2.Equilibrium-II (Ionic Equilibrium)
hard
$BaCl_2$ ની દ્રાવ્યતા $4 \times10^{-6}$ છે તો $K_{sp}$ શોધો. $10^{-2} M $ $ Ba(OH)_2$ ની હાજરીમાં નવી દ્રાવ્યતા શોધો.
A
$64 \times 10^{-6}$
B
$256 \times10^{-12}$
C
$256 \times10^{-18}$
D
$8 \times 10^{-8}$
Solution
$BaCl_2 \rightleftharpoons Ba^{+2} + 2Cl^{-}$
$1$ $s$ $2s$
$Ba(OH)_2 \rightleftharpoons Ba^{+2}+ 2OH^{-}$
$Ba(OH)^2\rightleftharpoons Ba^{+2}+ 2OH^{-}$
$C$ $0$ $0$
$0$ $C$ $2C$
$BaCl_2 ⇌ Ba^{+} + 2Cl^{-}$
$1$ $s' + C$ $2s'$
$K_{sp} = [Ba^{+2}] [Cl^{-2}]$
$K_{sp} = (s' + C)(2s')^2 = 4s'^33 + 4s'^2C$
$K_{sp }= 4s'^2C$
$K_{sp} = 4s^3 = 4 \times (4 \times10^{-6})^3 = 4 \times 64 \times 10^{-18} = 256 \times 10^{-18}$
Standard 11
Chemistry
