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6-2.Equilibrium-II (Ionic Equilibrium)
hard

જો $Mg(OH)_2$ નું સંતૃપ્ત દ્રાવણનું $4 \times 10^{-12} \,K_{sp}$ હોય તો $pH$ $=......$

A

$11.5$

B

$10.3$

C

$12.1$

D

$14.8$

Solution

$Mg(OH)_2 \rightleftharpoons  Mg^{+2} + 2OH^-$

          $ 1$             $s$           $2s$

$K_{sp} = 4s^2   ⇒ 4 \times  10^{-12} = 4s^3  ⇒ 10^{-12} = s^3  ⇒ s = (10^{-12})^{1/3}  = 10^{-4}$

$OH^- = 2s = 2 \times  10^{-4}$

$pOH = -log (2 \times  10^{-4}) = -log 2 + 4 = – 0.3010 + 4 = 3.7$

$pH = 14 – 3.7 = 10.3$

Standard 11
Chemistry

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