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12.Kinetic Theory of Gases
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${10^{ - 3}}\,{m^3}$ કદ ધરાવતા પાત્રમાં અણુનું દળ $5.3 \times {10^{ - 26}}$ kg ધરાવતા વાયુના અણુ $3.0 \times {10^{22}}$ છે,અણુની rms ઝડપ $400\, m/s$ છે,તો દબાણ
A
$8.48 \times {10^4}$$N/{m^2}$
B
$2.87 \times {10^4}$$N/{m^2}$
C
$25.44\, \times \,{10^4}$$N/{m^2}$
D
$12.72 \times {10^4}$$N/{m^2}$
Solution
$V = {10^{ – 3}}{m^3}$, $N = 3.0 \times {10^{22}}$, $m = 5.3 \times {10^{ – 26}}kg$, ${v_{rms}} = 400\,m/s$
$P = \frac{1}{3}\frac{{mN}}{V}v_{rms}^2 = \frac{1}{3} \times \frac{{5.3 \times {{10}^{ – 26}} \times 3.0 \times {{10}^{22}}}}{{{{10}^{ – 3}}}}{(400)^2} = 8.48 \times {10^4}\,N/{m^2}$.
Standard 11
Physics
