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$F_2$ generation in a Mendelian cross showed that both genotypic and phenotypic ratios are same as $1 : 2 : 1$. It represents a case of
codominance
dihybrid cross
monohybrid cross with complete dominance
monohybrid cross with incomplete dominance.
Solution
(d): The inheritance of flower colour in the dog flower (snapdragon or Antirrhinum $sp$.) is a good example which shows incomplete dominance. In a cross between truebreeding redflowered $(RR)$ and truebreeding whiteflowered plants $(rr)$, the $F_1\ (Rr)$ was pink. When the $F_1$ was selfpollinated the $F_2$ resulted in the following ratio, $1\ (RR)$ Red : $2\ (Rr)$ Pink : $1\ (rr)$ White. Here the genotype ratios were $1 : 2: 1$ as in any Mendelian monohybrid cross, but the phenotype ratios had changed from the $3 : 1$ dominant: recessive ratio to $1 : 2 : 1.$