$AlF_3$ is soluble in $HF$ only in presence of $KF.$ It is due to the formation of

  • [NEET 2016]
  • A

    $K_3[AlF_3H_3]$

  • B

    $K_3[AlF_6]$

  • C

    $AlH_3$

  • D

    $K[AlF_3H]$

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