Gujarati
Hindi
5.Work, Energy, Power and Collision
normal

$A$ small block of mass $m$ is placed on $a$ wedge of mass $M$ as shown, which is initially at rest. All the surfaces are frictionless . The spring attached to the other end of wedge has force constant $k$. If $a'$ is the acceleration of $m$ relative to the wedge as it starts coming down and $A$ is the acceleration acquired by the wedge as the block starts coming down, then  Maximum retardation of $M$ is:

A

$\sqrt {\frac{{2mghk}}{{{M^2}}}} $

B

$\sqrt {\frac{{2kgh}}{M}} $

C

$\sqrt {\frac{{2kgh}}{m}} $

D

None

Solution

Solution is Lorem ipsum dolor sit amet, consectetur adipiscing elit. Ut elit tellus, luctus nec ullamcorper mattis, pulvinar dapibus leo.
Standard 11
Physics

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