A ring of mass m and radius R has three parti | vedclass

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Question

About instantaneous axis of rotation rolling system can be considered as pure rotation

$K E=\frac{1}{2} I \omega^{2}$$...(1)$

here $I=$ moment o

Vedclass · Accepted Answer

$6\, mv_0^2$

Vedclass · Answer

About instantaneous axis of rotation rolling system can be considered as pure rotation

$K E=\frac{1}{2} I \omega^{2}$$...(1)$

here $I=$ moment of inertia about instantaneous axis of rotation

$I=2 m(\sqrt{2} R)^{2}+m(2 R)^{2}+m(\sqrt{2} R)^{2}+I_{r \in g}$

$I=2 m(\sqrt{2} R)^{2}+m(2 R)^{2}+m(\sqrt{2} R)^{2}+m R^{2}$

$I=12 m R^{2}$

putting the value of $I$ in equation $(1)$

$K E=6 m R^{2} \omega^{2}$

$K E=6 m(R \omega)^{2}$

$K E=6 m v_{o}^{2}$

$A$ ring of mass $m$ and radius $R$ has three particles attached to the ring as shown in the figure. The centre of the ring has a speed $v_0$. The kinetic energy of the system is: (Slipping is absent)

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