$2\ kg$ ice at $-20^o\ C$ is mixed with $5\ kg$ water at $20^o\ C$. Then final amount of water in the mixture would be ; Given specific heat of ice $= 0.5\ cal/g^o\ C$, specific heat of water $= 1\ cal/g^o\ C$, Latent heat of fusion of ice $= 80\ cal/g$ ........ $kg$
$2\ kg$ ice at $-20^o\ C$ is mixed with $5\ kg$ water at $20^o\ C$. Then final amount of water in the mixture would be ; Given specific heat of ice $= 0.5\ cal/g^o\ C$, specific heat of water $= 1\ cal/g^o\ C$, Latent heat of fusion of ice $= 80\ cal/g$ ........ $kg$
- A
$6$
- B
$5$
- C
$4$
- D
$2$
Similar Questions
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