$A$ chain of length $L$ and mass $m$ is placed upon a smooth surface. The length of $BA$ is $L-b$. Calculate the velocity of the chain when its end reaches $B$.
$\sqrt { \frac{{2g\,\sin \,\theta }}{L}\left( {{L^2} - {b^2}} \right)}$
$2\sqrt { \frac{{g\,\sin \,\theta }}{L}\left( {{L^2} - {b^2}} \right)}$
$\sqrt { \frac{{g\,\sin \,\theta }}{L}\left( {{L^2} - {b^2}} \right)}$
$\sqrt { \frac{{g\,\sin \,\theta }}{{2L}}\left( {{L^2} - {b^2}} \right)} $
A proton of mass $m$ collides elastically with a particle of unknown mass at rest. After the collision, the proton and the unknown particle are seen moving at an angle of $90^o$ with respect to each other. The mass of unknown particle is
Two identical balls $A$ and $B$ having velocities of $0.5\, m s^{-1}$ and $-0.3 \, m s^{-1}$ respectively collide elastically in one dimension. The velocities of $B$ and $A$ after the collision respectively will be
A ball hits the floor and rebounds after inelastic collision. In this case
Two balls of equal mass undergo head on collision while each was moving with speed $6 \,m / s$. If the coefficient of restitution is $\frac{1}{3}$, the speed of each ball after impact will be ............ $m / s$
Explain the total linear momentum is conserved in an elastic collision and also explain the inelastic collision and completely elastic collision.