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$H_3BO_3$ $\xrightarrow{{{T_1}}}X\xrightarrow{{{T_2}}}Y\xrightarrow{{red\,hot}}$ $B_2O_3$
if $T_1 < T_2$ then $X$ and $Y$ respectively are
$X =$ Metaboric acid and $Y =$ Tetraboric acid
$X =$ Tetraboric acid and $Y =$ Metaboric acid
$X =$ Borax and $Y =$ Metaboric acid
$X =$ Tetraboric acid and $Y =$ Borax
Solution
Effect of temperature at $100^{\circ} C , H _3 BO _3$ losses water and convert into metaboric acid.
$H _3 BO _3 \stackrel{100^{\circ} C }{\longrightarrow} HBO _2+ H _2 O$
metaboric acid form tetraboric acid on heating at $160^{\circ} C$
$4 HBO _2 \stackrel{160^{\circ} C }{\longrightarrow} H _2 B _4 O _7+ H _2 O$
On strong heating, $B _2 O _3$ is produced
$H _2 B _4 O _7 \rightarrow 2 B _2 O _3+ H _2 O$
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