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General Principles and processes of Isolation of Elements
medium
$(I)$ $FeCr_2O_4+NaOH +$ air $\rightarrow (A)+Fe_2O_3$
$(II)$ $(A)+(B) \rightarrow Na_2Cr_2O_7$
Compounds $(A)$ and $(B)$ are :
A
$Na_2CrO_4,\, H_2SO_4$
B
$Na_2Cr_2O_7 ,\, HCl$
C
$Na_2CrO_5, \,H_2SO_4$
D
$Na_4[Fe(OH)_6],\, H_2SO_4$
Solution
Compounds $(A)$ and $(B)$ are $Na _2 CrO _4$ and $H _2 SO _4$.
$FeCr _2 O _4+ NaOH +$ air $\rightarrow$ (A) $Na _2 CrO _4+ Fe _2 O _3$
$\underset{\text { (A) }}{ Na _2 CrO _4}+\underset{\text { (B) }}{ H _2 SO _4} \rightarrow Na _2 Cr _2 O _7$
Standard 12
Chemistry
