${H_3}B{O_3} + {H_2}O_2 \to {H_2}O + 'X' {\xrightarrow{{NAOH}} }{'Y'}$
Which of the following statements is $/$ are Correct for $'Y'$
Boron atom $(s)$ in $(Y)$ are $sp^3$ hybridised
There are two peroxy linkages in $Y$
$'Y'$ is used as brightener in washing powder
All of these
The bond dissociation energy of $B- F$ in $BF_3$ is $646 \,kJ\, mol^{-1}$ whereas that of $C - F$ in $CF_4$ is $515\, kJ\, mol^{-1}.$ The correct reason for higher $B- F$ bond dissociation energy as compared to that of $C-F$ is
A compound $(A)$ of boron reacts with $NMe_3$ to give an adduct $(B)$ which on hydrolysis gives a compound $(C) $ and hydrogen gas. Compound $(C)$ is an acid. Identify the compounds $A, B$ and $C.$ Give the reactions involved.
$H_3BO_3$ $\xrightarrow{{{T_1}}}X\xrightarrow{{{T_2}}}Y\xrightarrow{{red\,hot}}$ $B_2O_3$
if $T_1 < T_2$ then $X$ and $Y$ respectively are
Is boric acid a protic acid? Explain.
${H_3}B{O_3}\,\xrightarrow{{{T_1}}}X\,\xrightarrow{{{T_2}}}Y\,\xrightarrow{{\operatorname{Re} d\,\,\,hot}}{B_2}{O_3}$
if $T_1 < T_2$ then $X$ and $Y$ respectively are