A 43, m long rope of mass 5.0, kg joins two rock climbers. One climber strikes the rope a

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14.Waves and Sound

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A $43\, m$ long rope of mass $5.0\, kg$ joins two rock climbers. One climber strikes the rope and the second one feels the effect $1.4\, s$ later. What is the tension in the rope .... $N$ ?

A

$110$

B

$301$

C

$215$

D

$154$

Solution

$\mathrm{V}_{\text {wave }}=\frac{43}{1.4} \mathrm{\,m} / \mathrm{s}$

$\mathrm{V}_{\text {wave }}=\sqrt{\frac{\mathrm{T}}{\mu}} \Rightarrow \mathrm{T}=\mathrm{V}_{\text {wave }}^{2} \mu$

$=\left(\frac{43}{1.4}\right)^{2} \times \frac{5}{43} \approx \frac{43}{1.96} \times 5=109.69 \mathrm{\,N}$

Standard 11

Physics

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