A 30,μ F capacitor is charged by a constant current of 30, mA . If capacitor is initially uncharged

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2. Electric Potential and Capacitance

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A $30\,\mu F$ capacitor is charged by a constant current of $30\, mA$. If the capacitor is initially uncharged, how long does it take for the potential difference to reach $400\, V$.....$s$

A

$0.1$

B

$0.2$

C

$0.3$

D

$0.4$

Solution

$\mathrm{Q}=\mathrm{CV}=30 \times 10^{-6} \times 400=12 \times 10^{-3} \mathrm{\,C}$

$\mathrm{t}=\frac{\mathrm{Q}}{\mathrm{I}}=\frac{12 \times 10^{-3}}{30 \times 10^{-3}}=0.4 \mathrm{\,sec}$

Standard 12

Physics

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