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2. Electric Potential and Capacitance
easy
A $12\,pF$ capacitor is connected to a $50\,V$ battery. How much electrostatic energy is stored in the capacitor
A
$1.5 \times {10^{ - 8}}\,J$
B
$2.5 \times {10^{ - 7}}\,J$
C
$3.5 \times {10^{ - 5}}\,J$
D
$4.5 \times {10^{ - 2}}\,J$
Solution
(a) $U = \frac{1}{2}C{V^2} = \frac{1}{2} \times 12 \times {10^{ – 12}} \times {(50)^2}$$ = 1.5 \times {10^{ – 8}}\,J$
Standard 12
Physics